Methods

• void recordLapTiming(int carId, int lapId, int timeTaken)
  • carId and lapId will always be valid.
  • timeTaken will always be a positive integer.
  • Assume each (carId, lapId) is recorded at most once.
• List<String> getTop3FastestLaps()
  • Returns up to 3 entries sorted by increasing timeTaken.
  • Each entry format: carId-lapId-timeTaken
  • If fewer than 3 laps exist, return all of them.
  • Tie-breakers when timeTaken is the same:
    1. Lower carId first
    2. If still tied, lower lapId first
• List<Integer> getTop3Drivers()
  • Consider only drivers that have recorded at least one lap.
  • Driver average = totalTime / lapsRecorded (use a precise average, not integer division).
    Round average upto two decimal places using Math.round(value * 100.0) / 100.0
  • Returns up to 3 driver IDs sorted by:
    1. Faster (smaller) average first
    2. If tied, lower carId first

Examples

Example 1: Fewer than 3 laps recorded

Assume carsCount = 4, lapsCount = 3.

recordLapTiming(1, 0, 70)
recordLapTiming(2, 0, 69)

getTop3FastestLaps() -> ["2-0-69", "1-0-70"]
getTop3Drivers()     -> [2, 1]

Example 2: Ties + averages change over time

// continue from Example 1
recordLapTiming(3, 0, 69)

getTop3FastestLaps() -> ["2-0-69", "3-0-69", "1-0-70"]
getTop3Drivers()     -> [2, 3, 1]

// more laps
recordLapTiming(2, 1, 71)  // car2 avg = (69+71)/2 = 70.0
recordLapTiming(3, 1, 65)  // car3 avg = (69+65)/2 = 67.0
recordLapTiming(1, 1, 66)  // car1 avg = (70+66)/2 = 68.0

getTop3FastestLaps() -> ["3-1-65", "1-1-66", "2-0-69"]
getTop3Drivers()     -> [3, 1, 2]